Excuus voor mijn luiheid om mijn onbeantwoorde vraag op een engelstalig forum rechtstreeks te copy-pasten. Maar ik ga er van uit dat u allen de Engelse taal machtig bent Reacties mogen wat mij betreft in elke taal van uw voorkeur.
Hey everyone,
I'm doing research in international business. I will skip the details and get too my basic problem directly.
I have 300 firms in my sample, for which I have 5 yearly numbers of total sales.
For each firm I would like to calculate a variable that catches the trend in (negative) sales growth. I need a (trend) variable for sales growth in a regression analysis.
Visualizing this one can easily plot trend lines in a spread diagram in Excel. These graphs express the trend I want to translate into a variable that allows me for comparison between firms.
Is there any formula?
I will give an example for one firm:
Sales between 2005-2008:
2005: 193145
2006: 154512
2007: 448355
2008: 524282
2009: 586035
trend line formula: y=115555x +34601 (where y=total sales and x=time (t1,t2.. etc)
I know that it is not difficult to calculate a steepness variable of the lineair graph (íf you know two couples of x and y, but I can't catch these). I can't find out how in Excel. Neither in SPSS.
Besides it would be way easier if I could use a formula, so I won't have to calculate each variable independently.
THANK YOU IN ADVANCE!
Groeifactor bereken van trendlijn van spreidingsdiagram
- meneer van Hoesel
- Vergevorderde
- Berichten: 395
- Lid geworden op: 20 apr 2010, 14:43
- Locatie: Zwolle
Re: Groeifactor bereken van trendlijn van spreidingsdiagram
in Numbers (Apple) kun je beide waarden voor je trendlijn uitrekenen met SLOPE(y-waarden; x-waarde) en INTERCEPT(y-waarden; x-waarde)raulz schreef:trend line formula: y=115555x −231537619.2 (where y=total sales and x=time (t1,t2.. etc)
Code: Selecteer alles
Company 2005 2006 2007 2008 2009 Slope Intercept
Akzo 193145 154512 448355 524282 586035 115555 -231537619.2
BP
CocaCola
...
G3=SLOPE($B3:$F3;$B$1:$F$1)
H3=INTERCEPT($B3:$F3;$B$1:$F$1)
Hopenlijk is dit wat je zocht.
m.vr.gr.
meneer van Hoesel